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30/9/17 Answer is (ab)/2 int_a^b f(x) dx Let "I" be the integral, I = int_a^b xf(x) dx (1) Using the property of definite integrals, I = int_a^b (abx) f(abx) dx It is given that, f (abx) = f(x) implies I = int_a^b (abx) f(x) dx implies I = (ab) int_a^bf(x) dx int_a^b x f(x) dxEOTW y2 _ Z b g z C ~ l V C g 100LED 10M X g O C g \ d d W G C g C C g 8 _ h IP65 h X ܃f B X v C L v A E g h A N X } X O ̏ d F,DIYTitle Thomas Nicholas Salzano Author US Securities and Exchange Commission Subject Complaint Keywords Release No LR; Printable Phonetic Alphabet Etsy –{'I ƒfƒBƒXƒvƒŒƒCƒ‰ƒbƒN diy

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